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(3n^2=n-25)
We move all terms to the left:
(3n^2-(n-25))=0
We calculate terms in parentheses: +(3n^2-(n-25)), so:We get rid of parentheses
3n^2-(n-25)
We get rid of parentheses
3n^2-n+25
We add all the numbers together, and all the variables
3n^2-1n+25
Back to the equation:
+(3n^2-1n+25)
3n^2-1n+25=0
a = 3; b = -1; c = +25;
Δ = b2-4ac
Δ = -12-4·3·25
Δ = -299
Delta is less than zero, so there is no solution for the equation
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